Two short magnets are kept on opposite arms of the DMM at 12 cm and 16 cm. If there is no deflection in the needle, the ratio of the magnetic moments is :

3 : 4

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4 : 3

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9 : 14

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27 : 64

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Solution

The correct option is D 27 : 64
The deflection of the magnetic needle in tan A position by a short magnet is given by ,

$\frac{μ_{o}}{4 π} \frac{2 M_{A}}{d^{3}} = B_{H} t a n θ_{A}$

Since the deflection is zero ,
$\frac{M_{A}}{M_{B}} = \frac{d_{A}^{3}}{d_{B}^{3}}$

$\frac{M_{A}}{M_{B}} = 27 : 64$

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Two short magnets are kept on opposite arms of the DMM at 12 cm and 16 cm. If there is no deflection in the needle, the ratio of the magnetic moments is :

The correct option is D 27 : 64The deflection of the magnetic needle in tan A position by a short magnet is given by ,μo4π2MAd3=BHtanθASince the deflection is zero , MAMB=d3Ad3BMAMB=27:64