Two short Magnets having Magnetic moments in the ratio $27 : 8$ when placed on opposite sides of a deflection magnetometer shows no deflection. If the distance of weaker magnet is $0.12 m$ from the centre of D.M. The distance of the strongest magnet from the centre is ........... $m$

0.06

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0.08

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0.12

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0.18

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Solution

The correct option is D $0.18$
$\frac{M_{1}}{M_{2}} = {(\frac{d_{1}}{d_{2}})}^{3}$
$\frac{27}{8} = {(\frac{d_{1}}{0.12})}^{3}$
$\Rightarrow d_{1} = \frac{3}{2} \times 0.12 = 0.18 m$

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Two short Magnets having Magnetic moments in the ratio 27:8 when placed on opposite sides of a deflection magnetometer shows no deflection. If the distance of weaker magnet is 0.12 m from the centre of D.M. The distance of the strongest magnet from the centre is ...........m

The correct option is D 0.18M1M2=(d1d2)3278=(d10.12)3⇒d1=32×0.12=0.18m

Two short Magnets having Magnetic moments in the ratio $27 : 8$ when placed on opposite sides of a deflection magnetometer shows no deflection. If the distance of weaker magnet is $0.12 m$ from the centre of D.M. The distance of the strongest magnet from the centre is ........... $m$

The correct option is D $0.18$
$\frac{M_{1}}{M_{2}} = {(\frac{d_{1}}{d_{2}})}^{3}$
$\frac{27}{8} = {(\frac{d_{1}}{0.12})}^{3}$
$\Rightarrow d_{1} = \frac{3}{2} \times 0.12 = 0.18 m$