You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Ropes

Two unequal m...

Question

Two unequal masses (M $_{1}$ and M $_{2}$ ) are connected by a string which passes over a frictional pulley. If M $_{1}$ , M $_{2}$ and the table are frictionless, the acceleration of the masses would be

\frac{M_{1} g}{M_{1} + M_{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{M_{1} + M_{2}}{M_{1} g}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{M_{2} g}{M_{1} + M_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{M_{1} g}{M_{1} + M_{2}}$
Let tension developed in the string be $T$ .
Equations of motion are as follows-
$T = M_{2} a$
$M_{1} g - T = M_{1} a$
which gives, $a = g \frac{M_{1}}{M_{1} + M_{2}}$

Suggest Corrections

Similar questions

Q. Two unequal masses (

m_{1}

and

m_{2}

) are connected by a string which passes over a frictional pulley. If

M_{1}, M_{2}

and the table are frictionless, the acceleration of the masses would be

Q. Two unequal masses (

M_{1}

and

M_{2}

)are connected by a string which passes over a frictionless pulley (Fig. 3.1). If

M_{1}

M_{2}

and the table are frictionless, the acceleration of the masses would be

Q. A system consists of three masses

m_{1}, m_{2}

and

m_{3}

connected by a string passing over a pulley

P

. The mass

m_{1}

hangs freely and

m_{2}

and

m_{3}

are on a rough horizontal table (the coefficient of friction

= μ

). The pulley is frictionless and of negligible mass. The downward acceleration of mass

m_{1}

is (Assume

m_{1} = m_{2} = m_{3} = m

)

Two bodies of masses m₁ and m₂ are connected by a light, inextensible string, which passes over a frictionless pulley. If the pulley is moving upward with uniform acceleration g, then the tension in the string is

Q. Two masses

m_{1}

and

m_{2}

are connected by a light string passing over a smooth pulley. When set free

m_{1}

moves downward by 2 m in 2s. The ratio

m_{1} / m_{2}

is:

Join BYJU'S Learning Program

Two unequal masses (M1 and M2) are connected by a string which passes over a frictional pulley. If M1, M2 and the table are frictionless, the acceleration of the masses would be

The correct option is A M1gM1+M2Let tension developed in the string be T.Equations of motion are as follows-T=M2aM1g−T=M1awhich gives, a=gM1M1+M2

Two unequal masses (M $_{1}$ and M $_{2}$ ) are connected by a string which passes over a frictional pulley. If M $_{1}$ , M $_{2}$ and the table are frictionless, the acceleration of the masses would be

The correct option is A $\frac{M_{1} g}{M_{1} + M_{2}}$
Let tension developed in the string be $T$ .
Equations of motion are as follows-
$T = M_{2} a$
$M_{1} g - T = M_{1} a$
which gives, $a = g \frac{M_{1}}{M_{1} + M_{2}}$