Uncertainity in position of a hypothetical subatomic particle is 1 A and uncertainty in velocity is 3-3-4 - 105 m - s then the mass of the particle is approximately - h -6-6 - 10-34 J s -A- 2 - 10-29 kgB- 2 - 10-27 kgC- 2 - 10-29 kgD- 2 - 10-28 kg

Δ x × m × Δ v ≥ h/4π 1 × 10^ 10 × m × 3.3/4π × 10^5 ≥ 6.6 × 10^ 34/4 × π M = 2 × 10^ 29 kg ...

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Byju's Answer

Standard XII

Chemistry

Heisenberg's Uncertainty Principle

Uncertainity ...

Question

Uncertainity in position of a hypothetical subatomic particle is $1 Å$ and uncertainty in velocity is $\frac{3.3}{4 π} \times 10^{5} m / s$ then the mass of the particle is approximately $[h = 6.6 \times 10^{- 34} J s]$

2 × 10^-28 kg

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2 × 10^-27 kg

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2 × 10 ^-29 kg

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2× 10^-29 kg

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Solution

The correct option is C
2 × 10 ^-29 kg

$Δ x \times m \times Δ v \geq \frac{h}{4 π}$

$1 \times 10^{- 10} \times m \times \frac{3.3}{4 π} \times 10^{5} \geq \frac{6.6 \times 10^{- 34}}{4 \times π}$

$M = 2 \times 10^{- 29} k g$

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Uncertainity in position of a hypothetical subatomic particle is $1 Å$ and uncertainty in velocity is $\frac{3.3}{4 π} \times 10^{5} m / s$ then the mass of the particle is approximately $[h = 6.6 \times 10^{- 34} J s]$

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Uncertainity in position of a hypothetical subatomic particle is 1Å and uncertainty in velocity is 3.34π × 105 m/s then the mass of the particle is approximately [h = 6.6 × 10−34 Js]

The correct option is C 2 × 10 -29 kg Δx × m × Δv ≥ h4π 1 × 10−10 × m × 3.34π × 105 ≥ 6.6 × 10−344 × π M = 2 × 10−29 kg

Uncertainity in position of a hypothetical subatomic particle is $1 Å$ and uncertainty in velocity is $\frac{3.3}{4 π} \times 10^{5} m / s$ then the mass of the particle is approximately $[h = 6.6 \times 10^{- 34} J s]$

The correct option is C
2 × 10 ^-29 kg

$Δ x \times m \times Δ v \geq \frac{h}{4 π}$

$1 \times 10^{- 10} \times m \times \frac{3.3}{4 π} \times 10^{5} \geq \frac{6.6 \times 10^{- 34}}{4 \times π}$

$M = 2 \times 10^{- 29} k g$