Uncertainty in position of a 0.25g particle is 10−5. Uncertainty in velocity of that particle is:
(h=6.6×10−34Js)
A
1.2×10−34ms−1
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B
2.1×10−25ms−1
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C
1.6×10−29ms−1
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D
1.7×10−9ms−1
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Solution
The correct option is B2.1×10−25ms−1 According to the Heisenberg uncertainty principle, the exact momentum and position of a particle can’t be calculated simultaneously.
Mathematically represented as: Δp.Δx≥h4π Δx×(m×Δv)=h4π
⇒ Δv=hΔx×m×4π Δv=6.6×10−3410−5×(2.5×10−4)×3.14×4
= 2.1×10−25ms−1