Question

Uncertainty in position of a particle of 25 g in space is ${10}^{-5}m$. Hence, uncertainty in velocity (m/sec) is:

$[h=6.6\times {10}^{-34}J-Sec]$

• A. $2.1\times {10}^{-28}$
• B. $2.1\times {10}^{-34}$
• C. $0.5\times {10}^{-34}$
• D. $5\times {10}^{-24}$

Answer 1

Answer: (A)

$2.1\times {10}^{-28}$

$\Delta x={10}^{-5}m$

$m=0.025kg$

$\Delta x\times \Delta p=\frac{h}{4\pi }$

$\Delta x\times m\Delta v=\frac{h}{4\pi }$

$\Delta v=\frac{6.6\times {10}^{-34}}{4\times 3.14\times {10}^{-5}\times 0.025}$

$\Delta v=2.1\times {10}^{-28}m/sec$