Question

Using current division rule, find the current in each branch of the circuit shown in Fig.

Answer 1

Voltage across setup

$V=IR=\frac{15}{1000}\times 4.918=0.07377V$

$I$ in $10\Omega =\frac{V}{R}=0.007377A=7.377mA$

$I$ in $20\Omega =\frac{V}{R}=0.003688A=3.688mA$

$I$ in $30\Omega =\frac{V}{R}=0.002459A=2.459mA$

$I$ in $50\Omega =\frac{V}{R}=0.001475A=1.475mA$