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Question

Using Quadratic formula, solve the following quadratic equation for x.
p2x2+(p2q2)xq2=0

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Solution

p2x2+(p2q2)xq2=0=(p2q2)+(p2q2)2+4p2q22p2=q2p2±(p2+q2)2p2x=q2p2andx=1

Hence, this is the answer.

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