Using van der Waal's equation, calculate the constant a when 2 moles of a gas confined in a 4 L flask exerts a pressure of 11.0 atm at a temperature of 300 K. The value of b is 0.05Lmol−1.(as nearest integer)
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Solution
The van der Waal's equation of state for a gas is [P+an2V2](V−nb)=nRT ∴[11+a×2242](4−2×0.05)=2×0.0821×300 a=6.46atmL2mol−2 So, nearest integer value is 6.