Using x-ax-b-x2-a-bx-ab- find 103- 104-

103× 104 (100+3)(100+4) =(100)^2+(3+4)100+12 =10000+700+12 =10712 ...

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Cube Numbers

Using x+ax+...

Question

Using $(x + a) (x + b) = x^{2} + (a + b) x + a b,$ find $103 \times 104$ :

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Question 8(iii)
Using $(x + a) (x + b) = x^{2} + (a + b) x + a b$ , find
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