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Question

UV light of wavelength 300 nm and intensity 1 Wm2 falls on the surface of photo electric metal. If one percent of incident photons, produce photo electrons, then the number of photo electrons emitted from an area of 1.0 cm2 of the surface is nearly

A
2.13×1011s1
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B
1.5×1012s1
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C
3.02×1012s1
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D
3×1012s1
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Solution

The correct option is B 1.5×1012s1
E=hcλ=124003000=4.133eV=6.6×1019J
Power of source P=I×A=1×104=104W
No of photons per second =PE=1046.6×1019
Number of electrons =1100×1046.6×1019=1.5×1012s1

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