V-I graph for a metallic wire at two different temperatures $T_{1}$ and $T_{2}$ . Which of the two temperature $T_{1}$ and $T_{2}$ is higher and why?

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Solution

The slope of the given graph gives us the inverse of resistance. Resistance of a material increases with increasing the temperature. Because the collision between the molecules increases.
In the graph given, $T_{2}$ has smaller slope and hence corresponds to higher resistance. Therefore, $T_{2} > T_{1}$
or, $R = \frac{V}{I}$
if $V$ is a constant value, and $I_{1} > I_{2}$ , then $R_{1} < R_{2}$
But $R \propto T$ , hence $T_{1} < T_{2}$

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V-I graph for a metallic wire at two different temperatures T1 and T2. Which of the two temperature T1 and T2 is higher and why?

V-I graph for a metallic wire at two different temperatures $T_{1}$ and $T_{2}$ . Which of the two temperature $T_{1}$ and $T_{2}$ is higher and why?