Question

Vihaan spent ₹ $132$ to buy movie tickets for $20$ children and $4$ adults. Adult tickets cost ₹ $3$more than child tickets. If $A$ is the price of an adult ticket and $S$ is the price of a child ticket, which system of equations could be used to find the price of each adult and child ticket?

• A. $\left\{\begin{array}{l}S=A+3\\ 4A+20S=132\end{array}\right.$
• B. $\left\{\begin{array}{l}A=S+3\\ 4A+20S=132\end{array}\right.$
• C. $\left\{\begin{array}{l}A=S+3\\ 20A+4S=132\end{array}\right.$
• D. $\left\{\begin{array}{l}A=S+3\\ A+s=132\end{array}\right.$

Answer 1

The correct option is B

$\left\{\begin{array}{l}A=S+3\\ 4A+20S=132\end{array}\right.$

Explanation for the correct option:

Framing the equations to find the price of each adult and child ticket:

Given that,

The price of an adult ticket = $A$

The price of a child ticket = $S$

The price to buy movie tickets for $20$ children and $4$ adults is ₹$132$

Hence the equation can be written as $4A+20S=132$

The price of adult's ticket cost ₹$3$ more than child's ticket.

Hence the equation is $A=S+3$

The obtained equation are $\left\{\begin{array}{l}A=S+3\\ 4A+20S=132\end{array}\right.$

Therefore, the correct answer is option B