Vijay is pulling a block with 22N force and Gopal is pulling it with 10N force in the opposite direction. The block moves a distance of 6.5m in the same direction in which Vijay is pulling it. Calculate work done on the block.
A
80 J
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B
- 80 J
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C
- 78 J
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D
78 J
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Solution
The correct option is D 78 J Given:
Force applied by Vijay, F1=22N
Force applied by Gopal, F2=10N.
Displacement, s=6.5m
Since, both the forces are acting in the opposite directions, net force is given by: F=F1−F2 F=22−10=12N
The work done on the block is given by the product of displacement and the net force applied on it. Hence it is given by: W=F×s W=12×6.5=78J