Vijay is pulling a block with 22 N force and Gopal is pulling it with 10 N force in opposite direction. Vijay is able to pull the block to a total distance of 6.5 m. Find the net work done.

12 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

90 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

85 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

78 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
78 J

$W o r k d o n e = N e t f o r c e \times t o t a l d i s p l a c e m e n t = (22 - 10) \times 6.5 = 12 \times 6.5 = 78 J$

Suggest Corrections

Similar questions

Vijay is pulling a block with 22 N force and Gopal is pulling it with 10 N force in opposite direction. The block moves a distance of 6.5 m. Find the net work done.

Ankit is pulling a block with $22 N$ force and Gopal is pulling it with $10 N$ force in opposite direction. Ankit is able to pull the block to a total distance of $6.5 m .$ Find net work done.

Q. Vijay is pulling a block with

22 N

force and Gopal is pulling it with

10 N

force in the opposite direction. The block moves a distance of

6.5 m

in the same direction in which Vijay is pulling it. The work done on the block is:

Vijay and Gopal are pulling a block with 22 N force 10 N force respectively in opposite direction. If Vijay pulls the block by a total distance of 6.5 m towards himself. Find the net work done by the forces acting on the block.

Vijay is pulling a block with 22 N force and Gopal is pulling it with 10 N force in opposite direction. Vijay is able to pull the block a total distance of 6.5 m. Find the net work done by the two forces.

Join BYJU'S Learning Program

Vijay is pulling a block with 22 N force and Gopal is pulling it with 10 N force in opposite direction. Vijay is able to pull the block to a total distance of 6.5 m. Find the net work done.

The correct option is D 78 J Work done=Net force×total displacement=(22−10)×6.5=12×6.5=78J

The correct option is D
78 J

$W o r k d o n e = N e t f o r c e \times t o t a l d i s p l a c e m e n t = (22 - 10) \times 6.5 = 12 \times 6.5 = 78 J$