Viji is twice as old as his brother Deepu. If the difference of their ages is $11$ years, find their present age.

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Solution

Let the age of Deepu be $x$

Then, age of Viji will be $2 x$

Now as per the given condition, difference of their ages is $11$ years

$2 x - x = 11$

$\Rightarrow x = 11$

Thus, age of Deepu is $11$ years

Now, age of Viji is $2 x = 2 \times 11 = 22$ years.

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Viji is twice as old as his brother Deepu. If the difference of their ages is 11 years, find their present age.

Let the age of Deepu be xThen, age of Viji will be 2xNow as per the given condition, difference of their ages is 11 years2x−x=11⇒x=11Thus, age of Deepu is 11 yearsNow, age of Viji is 2x=2×11=22 years.

Viji is twice as old as his brother Deepu. If the difference of their ages is $11$ years, find their present age.

Let the age of Deepu be $x$

Then, age of Viji will be $2 x$

Now as per the given condition, difference of their ages is $11$ years

$2 x - x = 11$

$\Rightarrow x = 11$

Thus, age of Deepu is $11$ years

Now, age of Viji is $2 x = 2 \times 11 = 22$ years.