Question

Water rises in a vertical capillary tube upto a height of 2.0 cm. If the tube is inclined at an angle of ${60}^0$ with the vertical, then upto what length the water will rise in the tube:

• A. 2.0 cm
• B. 4.0 cm
• C. $\frac{4}{\sqrt{3}}$ cm
• D. $2\sqrt{2}$ cm

Answer 1

Answer: (B)

4.0 cm

As we know,

$l=\frac{h}{\cos \theta }$

$=\frac{2}{\cos {60}^0}=4.0cm$