Question

Water rises in a vertical capillary tube upto a length of 10 cm. If the tube is inclined at ${45}^0$, the length of water column risen in the tube will be

• A. 10 cm
• B. $10\sqrt{2}$ cm
• C. $5\sqrt{2}$ cm
• D. 20 cm

Answer 1

The correct option is B $10\sqrt{2}$ cm

given that:

$h_1=10cm$

then after :

let $P_0=\rho g{h}_1$

$h_1=\frac{P_0}{\rho g}=10cm$

now

$P_0={\rho gh}_2$

where $h_2=\frac{l}{\sqrt{2}}$

$\frac{P_0}{\rho g}=\frac{l}{\sqrt{2}}$

$l=10\sqrt{2}cm$

Correct option is (B).