Water strikes the blades of a turbine at the rate of $120 k g s^{- 1}$ . If the height of the fall is $120 m$ , calculate the power delivered to the turbine?
(Given $g = 10 m s^{- 2}$ )

120 k W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

133 k W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

144 k W

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

150 k W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $144 k W$
Given,
Mass m = $120 k g$ ,
Time t= $1 s e c$ ,
Height h= $120 m$ and
Acceleration due to gravity $g = 10 m s^{- 2}$ .
$Power = \frac{m g h}{t}$
$∴ \frac{120 \times 10 \times 120}{1 s} = 144, 000 w a t t s$
Power = $144, 000 w a t t s = 144 k W$

Suggest Corrections

Similar questions

From a water fall, water is falling at the rate of 100 kg/s on the blades of turbine. If the height of the fall is 100m then the power delivered to the turbine is approximately equal to

From a waterfall, water pours down at the rate of $100 k g s^{- 1}$ on the blades of a turbine. If the height of the fall is 120 m, what is the power delivered to the turbine?

From a waterfall, water pours down at the rate of $100 k g s^{- 1}$ on the blades of a turbine. If the height of the fall is 120 m, calculate the power delivered to the turbine?
(Given $g = 10 m s^{- 2}$ )

From a water fall, water is falling at the rate of 100 kg/s on the blades of turbine. If the height of the fall is 100m then the power delivered to the turbine is approximately equal to

Q. From a water fall , water is pouring down at the rate of 100 kg per sec on the blade of a turbine . If the height of the fall be 100 m, the power delivered to the turbine is approximately equal to :

Join BYJU'S Learning Program

Water strikes the blades of a turbine at the rate of 120 kgs−1. If the height of the fall is 120 m, calculate the power delivered to the turbine? (Given g=10 ms−2)

The correct option is C 144 kWGiven, Mass m = 120 kg, Time t= 1 sec, Height h= 120 m and Acceleration due to gravity g=10 ms−2. Power=mght ∴ 120×10×1201s=144,000 watts Power = 144,000 watts=144kW

Water strikes the blades of a turbine at the rate of $120 k g s^{- 1}$ . If the height of the fall is $120 m$ , calculate the power delivered to the turbine?
(Given $g = 10 m s^{- 2}$ )

The correct option is C $144 k W$
Given,
Mass m = $120 k g$ ,
Time t= $1 s e c$ ,
Height h= $120 m$ and
Acceleration due to gravity $g = 10 m s^{- 2}$ .
$Power = \frac{m g h}{t}$
$∴ \frac{120 \times 10 \times 120}{1 s} = 144, 000 w a t t s$
Power = $144, 000 w a t t s = 144 k W$