Question

What amount of $BaS{O}_4$ can be obtained on mixing 0.5 mole $BaC{l}_2$ with 1 mole of $H_{2}S{O}_4$ ?

• A. 0.5 mol
• B. 0.15 mol
• C. 0.1 mol
• D. 0.2 mol

Answer 1

Answer: (A)

0.5 mol

$0.5$ mole of barium chloride react with one mole of slphuric acid as follow:

$\underset{0}{\underset{0.5}{BaC{l}_2}}+\underset{(1-0.5)}{\underset{1}{H_{2}S{O}_4}}\to \underset{0.5}{\underset{0}{BaS{O}_4}}+\underset{2\times 0.5}{\underset{0}{2HCl}}$

Hence the amount produced by the reaction of bariumchloride and sulphuric acid is $0.5mol.$

Hence, te correct option is $\text{A}$