Question

What is likely to be orbit number for a circular orbit of diameter $20$ nm of the hydrogen atom?

• A. $10$
• B. $14$
• C. $12$
• D. $16$

Answer 1

The correct option is B $14$

Bohr radius is given as

$r_n=0.529n^2\times {10}^{-10}m$

Given the $diameter=20nm$

Therefore,radius = $10nm=10\times 10^{-9}m$

Using Bohr radius equation:

$n^2=\frac{10\times {10}^{-9}}{0.529\times {10}^{-10}}=189.03$

$n=13.74\approx 14$

Hence, the correct option is $B$