For a train that travels from one station to another station at a uniform speed of 40kmph and returns to the final station at 60kmph ,then it's average speed is? Convert into ms

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Solution

➡Complete solution :-

➡Let the distance between two stations = d km

➡After, the journey the train returns to the first station.

➡Total distance travelled = 2d
Net displacement of the train = 0

➡So, the train time taken to travel one station to another station = t1= d/40hrs

Time take by the train when come back , t2= d/60hrs

Therfore, total time taken by the train to round the trip is

t = t1+t2= d/40 + d/60 = d/24hrs

➡Avg . Speed = 2d/ d/24 = 48 km/ h

➡Avg. Velocity = 0/ d/24 = 0 km/ h

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