Question

What is the Bhors radius in the second orbit of ${Be}^{2+}$.

Answer 1

$r_n=a_0\left(n^2/z\right)$

For $B{e}^{2+}$

$Z=4$ and $n=2$

substituting the values

$r_n=52.9\times {10}^{-12}\left(4/4\right)=52.9\times {10}^{-12}$m