What is the coefficient of oxalate ion in the balanced form of following reaction? MnO−4+C2O2−4+H+⟶Mn2++CO2+H2O
A
4
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B
2
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C
3
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D
5
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Solution
The correct option is D 5 [MnO−4+8H++5e−⟶Mn2++4H2O]×2.....(i) [C2O2−4⟶2CO2+2e−]×5.....(ii)
Adding equation (i) and (ii) we get 2MnO−4+5C2O2−4+16H+⟶2Mn2++10CO2+8H2O
Thus, the coefficient of oxalate ion, C2O2−4 is 5.