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Question

What is the concentration of CO23 in a 0.1 M Na2CO3 solution after the hydrolysis reactions have come to an equilibrium? (Ka(HCO3)=4.7×1011)

A
2×104
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B
6.3×104
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C
2×104
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D
9.54×102
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Solution

The correct option is D 9.54×102
The first step of hydrolysis of CO23 ions is predominant.
CO23(aq)0.1(1h)+H2O(l)HCO3(aq)0.1h+OH(aq)0.1h
Kh=0.1h2(1h)

Kh=KwKa=1×10144.7×1011Kh=2.12×104

Finding CKh

CKh=0.12.12×104=471.7
Since CKh>100 , we can use 1h1
Kh=0.1×h2h=2.12×1040.1=0.046[CO23]eqb=0.1×(1h)=0.1×(10.046)[CO23]eqb=9.54×102

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