What is the correct order of size in each pair given below ?
$C u$ and $Z n$

C u

Z n

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C u

Z n

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C u

Z n

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None of these

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Solution

The correct option is B $C u$ < $Z n$
Towards the end of 3d series, electron pairing takes place in more of the d-orbitals, the repulsive interaction between the added electrons in each orbital is more than the attractive force due to the increase in the nuclear charge. Hence, the orbitals slightly expand and atomic radii marginally increase. This happens in the case of zinc.Option (B) is correct.

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Similar questions

The standard reducation potentials of

$Z n^{2 +} | Z n, C u^{2 +} | C u$ and $A g^{+} | A g$

are respectively -0.76, 0.34 and 0.8 V. The following cells were constructed.

a) $Z n | Z n^{2 +} | | C u^{2 +} | C u$

b) $Z n | Z n^{2 +} | | A g^{+} | A g$

c) $C u | C u^{2 +} | | A g^{+} | A g$

What is the correct order $E {^{0}}_{c e l l}$ of these cells?

The cell representation of the given reaction is:
Zn(s) + Cu²⁺ → Zn²⁺ + Cu(s)

Below given are emf of three galvanic cells, represented by $E_{1}$ , $E_{2}$ and $E_{3}$ . Which of the following is true?

I. $Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u$

II. $Z n | Z n^{2 +} (0.1 M) | | C u^{2 +} (1 M) | C u$

III. $Z n | Z n^{2 +} (1 M) | | C u^{2 +} (0.1 M) | C u$

Z n (s) + C u^{2 +} \to Z n^{2 +} + C u (s)

E^{o} Z n^{2 +} / Z n = - 0.74

E^{o} C u^{2 +} / C u = 0.36

What is the oxidizing agent in the following redox reaction?

$Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)$

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