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Byju's Answer
Standard XII
Physics
Reverse Bias
What is the c...
Question
What is the current through the resistor
2
Ω
in the circuit shown in figure.
A
5
/
2
A
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B
5
/
3
A
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C
10
/
3
A
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D
3
/
2
A
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Solution
The correct option is
A
5
/
2
A
Equivalent circuit of the above figure is shown.
Net resistance of
3
Ω
and
6
Ω
,
R
A
B
=
3
∥
6
=
3
×
6
3
+
6
=
2
Ω
Net resistance of
4
Ω
and
4
Ω
,
R
C
D
=
4
∥
4
=
2
Ω
Thus equivalent resistance of the circuit
R
e
q
=
2
+
(
6
∥
6
)
=
2
+
3
=
5
Ω
Current flowing through the battery
I
=
V
R
e
q
=
25
5
=
5
A
∴
Current through
2
Ω
,
I
′
=
I
2
=
5
2
A
Suggest Corrections
0
Similar questions
Q.
A current
3
A
flows through
2
Ω
resistor as shown in the circuit. The power dissipated in the
5
Ω
resistor is
Q.
Find out the current through
2
Ω
resistor in the circuit shown in figure.
Q.
Divide:
(
6
a
5
+
8
a
4
+
8
a
3
+
2
a
2
+
26
a
+
35
)
by
(
2
a
2
+
3
a
+
5
)
Answer:
3
a
3
−
3
a
2
+
a
+
7
Q.
Factorize the following:
5
−
(
3
a
2
−
2
a
)
(
6
−
3
a
2
+
2
a
)
Q.
In the circuit shown in figure,
E
1
and
E
2
are two ideal sources of unknown emfs. Current flowing through resistor of resistance
R
Ω
is
2
A
and through resistor of resistance
4
Ω
is
3
A
as shown. If potential difference across
6
Ω
resistance is
V
A
−
V
B
=
10
V
, then the value of
(
E
2
−
E
1
)
R
( in
V
.
Ω
) is
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