What is the electronic configuration for tin?

[K r] 5 s^{2} 5 p^{2}

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[K r] 4 d^{10} 5 s^{2} 5 p^{2}

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1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{2}

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[K r] 4 d^{11} 5 s^{2} 5 p^{1}

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Solution

The correct option is A $[K r] 4 d^{10} 5 s^{2} 5 p^{2}$
The atomic number of tin (Sn) is $50$ .

Thus its electronic configuration is $[K r] 4 d^{10} 5 s^{2} 5 p^{2}$

or

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6} 4 d^{10} 5 s^{2} 5 p^{2}$ .

Hence, te correct option is $B$

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Similar questions

4 d^{10} 5 s^{2} 5 p^{2}

[K r] 4 d^{10}

[K r] 4 d^{10} 4 f^{14} 5 s^{2} 5 p^{6} 5 d^{1} 6 s^{2}

[K r] 4 d^{10}

Z

S r = 38

S n = 50

T e = 52

A g = 47

[K r] 4 d^{10}

Z

S r = 38

S n = 50

T e = 52

A g = 47

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