What is the enthalpy change for the given reaction, if enthalpies of formation of AI2O3 and Fe2O3 are -1670 kJmol−1 and -834 kJ mol−1 respectively. Fe2O3+2AI→AI2O3+2Fe
A
−836kJmol−1
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B
+836kJmol−1
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C
−424kJmol−1
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D
+424kJmol−1
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Solution
The correct option is C−836kJmol−1 ΔH=∑ΔHP−∑ΔHR = -1670 - (-834) = -836 kJ mol−1