Question

What is the equivalent mass of $I{O}_4^{-}$ when it is converted into $I_2$ in acid medium

• A. $\frac{M}{6}$
• B. $\frac{M}{7}$
• C. $\frac{M}{5}$
• D. $\frac{M}{4}$
• E. None of these

Answer 1

The correct option is B $\frac{M}{7}$

Equivalent mass
$=\frac{Molecularweight}{Changeinoxidationnumberpermole}$
Suppose molecular weight is M
Oxidation number of $I_{2}inI{O}_4^{-}$ in
Acidic medium i.e., $I\times (-8)+I{e}^{-}=+7$
So eq. wt. $\frac{M}{7}$.