What is the formula of bromodichloroiodopalladate(II) ion?

P d [B r C l_{2} I]^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[P d B r C l_{2} I]^{2 -}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[P d B r C l_{2} I]^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[P d B r C l_{2} I]^{3 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $[P d B r C l_{2} I]^{2 -}$
The formula of bromodichloroiodopalladate(II) ion is $[P d B r C l_{2} I]^{2 -}$ .

Palladate indicates that Pd atom is a part of the complex anion. It contains one bromine, one iodine and 2 chlorine atoms. Thus, the coordination number of Pd is 4.

Suggest Corrections

Similar questions

[I V P d (N H_{3})_{2} (H_{2} O)_{2} B r_{2}]^{2 +}

[P d (N H_{3})_{4}]^{2 +} 2 C l^{-}

C a^{2 +}

C H_{3} C O O^{-}

F e^{2 +}

1 / 8^{t h}

F e^{3 +}

\frac{1}{2}

Join BYJU'S Learning Program