Question

What is the hybridization of $Xe$ in $Xe{F}_6$?

• A. $s{p}^3{d}^3$
• B. $s{p}^{2}d$
• C. $s{p}^3{d}^2$
• D. $s{p}^3$

Answer 1

The correct option is A $s{p}^3{d}^3$

$Xe{F}_6$: $Xe$ is having a total of 8 outer electrons out of which 6 are used for forming bonds with $F$ and one lone pair will be present on the central atom.
Thus, it has 6 bond pairs and 1 lone pair$\Rightarrow s{p}^3{d}^3$ hybridization.