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Standard IX

Chemistry

Atomic Mass and Atomic Mass Unit

What is the m...

Question

What is the molar mass of ammonium carbonate ${({N H}_{4})}_{2} {C O}_{3}$ ?

48 g / m o l

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96 g / m o l

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82 g / m o l

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78 g / m o l

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192 g / m o l

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Solution

The correct option is A $96 g / m o l$
$(N H_{4})_{2} C O_{3}$ is the chemical formula of ammonium carbonate.

$N = 14 \times (2) = 28$
$H = 1 \times (4 \times 2) = 8$
$C = 12 \times 1 = 12$
$O = 16 \times 3 = 48$

Molar mass $= 28 + 8 + 12 + 48 = 96 g / m o l$

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Similar questions

Q. Statement 1: A

1.0

g sample of calcium citrate

C a_{3} (C_{6} H_{5} O_{7})_{2}

(molar mass

= 498

g/mol), contains more

C a

than a

1.0

g sample of calcium carbonate,

C a C O_{3}

(molar mass

= 100

g/mol)
Statement 2: There are more

C a

atoms in

1.0

mol of calcium carbonate than in

1.0

mol of calcium citrate.

Q. What is the value of

x

where:

x = 9.4 g + 6.023 \times 10^{23} m o l e c u l e s - 0.2 m o l

x

is phenol which has a molar mass of

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Q. The

%

of nitrogen is (as nearest integer) :
[Molar mass of

{(N H_{4})}_{2} C_{2} O_{4} = 124.10

g/mol and atomic mass of

N = 14.0078

]

Q. The mass of

A l (O H)_{3}

that was obtained by the reaction of 133.4 g of

A l C l_{3}

with 40 g of

N a O H

according to following equation is 13 g.

A l C l_{3} + N a O H \to A l (O H)_{3} + N a C l

(not balanced)
Calculate the percentage yield.

(Molar mass of aluminium chloride is 133.34 g/mol, molar mass of

N a O H

is 40 g/mol and molar mass of aluminium hydroxde is 78 g/ mol respectively)

25.3 g

of sodium carbonate,

{N a}_{2} {C O}_{3}

is dissolved in enough water to make

250 m L

of solution. If sodium cabonate dissociates completely, molar concentration of sodium ion,

{N a}^{+}

and carbonate ion

{C O}_{3}^{2 -}

are respectively: (Molar mass of

{N a}_{2} {C O}_{3} = 106 g {m o l}^{- 1}

)

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What is the molar mass of ammonium carbonate (NH4)2CO3?

The correct option is A 96 g/mol(NH4)2CO3 is the chemical formula of ammonium carbonate.N=14×(2)=28H=1×(4×2)=8C=12×1=12O=16×3=48Molar mass =28+8+12+48=96 g/mol

What is the molar mass of ammonium carbonate ${({N H}_{4})}_{2} {C O}_{3}$ ?

The correct option is A $96 g / m o l$
$(N H_{4})_{2} C O_{3}$ is the chemical formula of ammonium carbonate.

$N = 14 \times (2) = 28$
$H = 1 \times (4 \times 2) = 8$
$C = 12 \times 1 = 12$
$O = 16 \times 3 = 48$

Molar mass $= 28 + 8 + 12 + 48 = 96 g / m o l$