What is the order of bond angle in of2 ocl2 oh2

Open in App

Solution

Dear student
The principle is that the larger the atoms on the two sides are, the wider the angle between them.
H₂O with two hydrogens and bond angle of 109.5^o
F₂O with two fluorine atoms and bond angle of 104.5^o
OCl₂ with two chlorine atoms and the bond angle of 109.47
Hence, the ascending order of bond angle is as follows,
F₂O < OCl₂ < H₂O
Regards

Suggest Corrections

Similar questions

H_{2} S

N H_{3}

B F_{3}

S i H_{4}

O F_{2}

O F_{2}, C l_{2} O, B r_{2} O

O F_{2}

O F_{2}, O C l_{2}, C l O_{2}

H_{2} O

H_{2} S, N H_{3}, B F_{3} a n d S i H_{4}

C l_{2} O

O F_{2}

Join BYJU'S Learning Program