Question

What is the oxidation number of sulphur in $H_{2}S{O}_4$?

Answer 1

Charge on hydrogen is +1 and charge on oxygen atom is -2.Total charge on $H_{2}S{O}_4$ is 0.

Let the oxidation state of sulphur be $x$

$\therefore 2(+1)+x+4(-2)=0$

$\therefore x-6=0$

$\therefore x=+6$

Therefore, the oxidation number of sulphur in $H_2{SO}_4$ in $+6$.