What is the phase difference between I and E if E - E0 sin- t and I - I0cos- t - -3-

E=E_0 sinω t I=I_0 cos(ω t+π/3) =I_0 cos(π/2+ω t+π/3) nbsp; Representing E and I in a phasor diagram nbsp; From the diagram, phase difference between n ...

258

You visited us 258 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Phasor Diagrams in AC Circuits

What is the p...

Question

What is the phase difference between $I$ and $E$ if $E = E_{0} sin (ω t)$ and $I = I_{0} cos (ω t + \frac{π}{3})$ ?

\frac{π}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{π}{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{π}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5 π}{6}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{5 π}{6}$
$E = E_{0} sin ω t$
$I = I_{0} cos (ω t + \frac{π}{3}) = I_{0} cos (\frac{π}{2} + ω t + \frac{π}{3})$

Representing $E$ and $I$ in a phasor diagram

From the diagram, phase difference between $E$ and $I$ is $\frac{5 π}{6}$

Suggest Corrections

Similar questions

Q. What is the phase difference between

I

and

E

E = E_{0} sin (ω t)

and

I = I_{0} cos (ω t + \frac{π}{3})

Q. If the instantaneous emf and the instantaneous current equations of an A.C. circuit are respectively

e = E_{0} sin (ω t - π / 6), i = I_{0} sin (ω t + π / 6)

, then the phase difference between voltage and current is :

Q. The instantaneous values of current and emf in an ac circuit are

I = \frac{1}{\sqrt{2}} s i n

314tamp and

E = \sqrt{2} s i n (314 t - \frac{Π}{6})

V respectively. The phase difference between E and I will be

Q. The phase difference between the alternating current and voltage represented by the following equation

I = I_{0} sin ω t, E = E_{0} cos (ω t + \frac{π}{3}),

will be

Q. The instantaneous values of current and emf in an ac circuit are

I = \frac{1}{\sqrt{2}} s i n

314tamp and

E = \sqrt{2} s i n (314 t - \frac{Π}{6})

V respectively. The phase difference between E and I will be

Join BYJU'S Learning Program

What is the phase difference between I and E if E=E0sin(ωt) and I=I0cos(ωt+π3)?

The correct option is D 5π6E=E0sinωt I=I0cos(ωt+π3)=I0cos(π2+ωt+π3) Representing E and I in a phasor diagram From the diagram, phase difference between E and I is 5π6

What is the phase difference between $I$ and $E$ if $E = E_{0} sin (ω t)$ and $I = I_{0} cos (ω t + \frac{π}{3})$ ?

The correct option is D $\frac{5 π}{6}$
$E = E_{0} sin ω t$
$I = I_{0} cos (ω t + \frac{π}{3}) = I_{0} cos (\frac{π}{2} + ω t + \frac{π}{3})$

Representing $E$ and $I$ in a phasor diagram

From the diagram, phase difference between $E$ and $I$ is $\frac{5 π}{6}$