What is the phase difference between I and E if E - E 0sin - t and I - I 0cos- t -3 -A- -3- -6- -2D- 5 -6

The correct option is D 5π6E=E_0 sinω t I=I_0 cos(ω t+π/3) =I_0 cos(π/2+ω t+π/3) nbsp; Representing E and I in a phasor diagram nbsp; From the diagram, ...

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Byju's Answer

Standard XII

Physics

Phasor Diagrams in AC Circuits

What is the p...

Question

What is the phase difference between $I$ and $E$ if $E = E_{0} sin (ω t)$ and $I = I_{0} cos (ω t + \frac{π}{3})$ ?

\frac{π}{3}

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\frac{π}{6}

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\frac{π}{2}

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\frac{5 π}{6}

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Solution

The correct option is D $\frac{5 π}{6}$
$E = E_{0} sin ω t$
$I = I_{0} cos (ω t + \frac{π}{3}) = I_{0} cos (\frac{π}{2} + ω t + \frac{π}{3})$

Representing $E$ and $I$ in a phasor diagram

From the diagram, phase difference between $E$ and $I$ is $\frac{5 π}{6}$

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What is the phase difference between I and E if E=E0sin(ωt) and I=I0cos(ωt+π3)?

The correct option is D 5π6E=E0sinωt I=I0cos(ωt+π3)=I0cos(π2+ωt+π3) Representing E and I in a phasor diagram From the diagram, phase difference between E and I is 5π6

What is the phase difference between $I$ and $E$ if $E = E_{0} sin (ω t)$ and $I = I_{0} cos (ω t + \frac{π}{3})$ ?

The correct option is D $\frac{5 π}{6}$
$E = E_{0} sin ω t$
$I = I_{0} cos (ω t + \frac{π}{3}) = I_{0} cos (\frac{π}{2} + ω t + \frac{π}{3})$

Representing $E$ and $I$ in a phasor diagram

From the diagram, phase difference between $E$ and $I$ is $\frac{5 π}{6}$