A manometer is connected to a flask containing a gas. The open arm reads 36.2 cm whereas the arm connected to the Hg, the gas pressure in atm is ?

1.0 atm

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1.25 atm

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1.30 atm

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1.45 atm

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Solution

The correct option is B 1.25 atm
Gas pressure = barometric pressure + pressure due to Hg column
$743 m m H g + (36.2 - 15.5) \times 10 m m H g = 950 m m H g$
$= \frac{950}{760} = 1.25 a t m$

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Standard XII Chemistry

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A manometer is connected to a flask containing a gas. The open arm reads 36.2 cm whereas the arm connected to the Hg, the gas pressure in atm is ?

The correct option is B 1.25 atmGas pressure = barometric pressure + pressure due to Hg column 743 mm Hg+(36.2−15.5)×10 mm Hg=950 mm Hg =950760=1.25 atm

The correct option is B 1.25 atm
Gas pressure = barometric pressure + pressure due to Hg column
$743 m m H g + (36.2 - 15.5) \times 10 m m H g = 950 m m H g$
$= \frac{950}{760} = 1.25 a t m$