Question

What is the pressure exerted by a woman weighing $500N$ standing on one heel of area of $1c{m}^2$?

Answer 1

Force exerted by the women = Her weight = $500N$
Area on which force acts $=1c{m}^2={\left(\begin{array}{c}\frac{1}{100}m\end{array}\right)}^2$
$=\frac{1}{10000}{m}^2$
$\therefore Pressure=\frac{Force}{Area}=\frac{500N}{\frac{1}{10000}{m}^2}$
$=500\times 10000N{m}^{-2}=5\times {10}^{6}N{m}^{-2}$.