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Question

What is the ratio of the empirical formula mass to the molecular formula mass of benzene?

A

1 : 6

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B

2 : 3

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C

6 : 1

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D

3 : 2

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Solution

The correct option is A $1 : 6$
Molecular formula of benzene $= C_{6} H_{6}$
Molecular formula mass of benzene $= 78$
Empirical formula of benzene $= C H$
Empirical formula mass of benzene $= 13$

$∴ \frac{empirical formula mass}{molecular formula mass} = \frac{13}{78} = 1 : 6$

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