What is the structure of Diamidotetraamminecobalt (III) ethoxide

[C o (N H_{2})_{2} (N H_{3})_{4}] O C_{2} H_{5}

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[C o (N H_{2})_{4} (N H_{3})_{2}] O C_{2} H_{5}

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[C o (N H_{2})_{4} (N H_{3})_{2} O C_{2} H_{5}]

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None of the above

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Solution

The correct option is A $[C o (N H_{2})_{2} (N H_{3})_{4}] O C_{2} H_{5}$
The cation is always named before the anion!
Since we know that ethoxide $C_{2} H_{5} O^{-}$ is the anion (with a single negative charge),
the cation must be a complex with a single positive charge.

The given name can be broken into as:
Di-amido $\Rightarrow$ as in there are two amide groups - $N H_{2}^{-}$ .
tetraammine $\Rightarrow$ which implies there are 4 $N H_{3}$ groups!
The central metal of the complex cation is $C o (I I I)$
Hence: $[C o (N H_{2})_{2} (N H_{3})_{4}] O C_{2} H_{5}$

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