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Question
What is the volume of water that must be added to a mixture of 250 ml of 6M HCl solution and 650 ml of 3M HCl solution to obtain a 3M solution?
What is the volume of water that must be added to a mixture of 250 ml of 6M HCl solution and 650 ml of 3M HCl solution to obtain a 3M solution?
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Solution
The correct option is D 250ml
When two solutions are mixed together to form a solution, we apply the formula:
M1V1+M2V2=M×V, where M1,M2,V1,V2 are the molarity and volume of the solutions being mixed, and M and V are the molarity and volume of the final solution.
250×6+650×3=3×V
⟹V=1150 ml
The total volume of the solution is 1150 ml. The volume present initially is (250+650)=900 ml solution. We need to add 250 ml of water to obtain a 3 M solution.
Hence, the correct option is D
When two solutions are mixed together to form a solution, we apply the formula:
M1V1+M2V2=M×V, where M1,M2,V1,V2 are the molarity and volume of the solutions being mixed, and M and V are the molarity and volume of the final solution.
250×6+650×3=3×V
⟹V=1150 ml
⟹V=1150 ml
The total volume of the solution is 1150 ml. The volume present initially is (250+650)=900 ml solution. We need to add 250 ml of water to obtain a 3 M solution.
Hence, the correct option is D
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