What is the work to be done to increase the velocity of an object from $1 m / s t o 5 m / s$ . The mass of the object is 10 kg.

30 J

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60 J

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90 J

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120 J

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Solution

The correct option is D 120 J
Mass of the object: 10 kg
Initial velocity $= 1 m s^{- 1}$
Final Velocity $= 5 m s^{- 1}$
Work Done = Change in kinetic energy = Final Kinetic Energy - Initial kinetic Energy
$= \frac{1}{2} m v^{2} - \frac{1}{2} m u^{2}$
$= \frac{1}{2} m (v^{2} - u^{2})$
$= \frac{1}{2} 10 (5^{2} - 1^{2})$
= 120 J

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