What mass of CaCO₃ is required to react completely with 25ml of 0.75M of HCL.

Open in App

Solution

First calculate the mass of HCl that is present in 25 mL of 0.75 M HCl solution. Molarity of a solution is given by the following relation
Molarity = number of moles of solute / Volume of solution (in litres)

0.75 = n / 0.025

This gives n = 0.01875

Now, number of moles is given by the following realtion

number of moles = mass of substance / molar mass of substance

So, the mass of HCl will be

0.01875 = mass of HCl / 36.5

mass of HCl = 0.684g

Now, a balanced chemical equation showing the reaction of HCl and CaCO3is as follows

CaCO3 + 2HCl → CaCl2 + H2O + CO2

According to the above equation, 100g of CaCO3 is required to react completely with 71g of HCl. That is

73g of HCl → 100g of CaCO3

1g of HCl → (100 / 73) g of CaCO3

So, 0.684g would require = (100 / 73) X 0.684 g of CaCO3

= 0.937g of CaCO3

Thus 0.937g of CaCO3 would be required to completely react with 25ml of 0.75M HCl.

Suggest Corrections

Similar questions

Q. According to the

C a C O_{3} + H C l \to C a C l_{2} + C O_{2} + H_{2} O

. What mass of

C a C O_{3}

is required to react completely with

25

ml. of

0.75 M

H C l

Calculate the mass of CaCO3 required to react completely with 25ml of 0.75M HCl

Calcium carbonate reacts with aqueous $HCl$ to give ${CaCl}_{2}$ and ${CO}_{2}$ according to the reaction given below

$\underset{Calcium Carbonate}{{CaCO}_{3} (s)} + \underset{Hydrochloric acid}{2 HCl (aq)} ⟶ \underset{Calcium Chloride}{{CaCl}_{2} (aq)} + \underset{Carbon dioxide}{{CO}_{2} (g)} + \underset{Water}{H_{2} O (l)}$

What mass of ${CaCO}_{3}$ is required to react completely with 25 mL of 0.75 M HCl?

1) 0.6844

2) 0.9375

3) 0.4265

4) 0.2785

Calcium carbonate reacts with aqueous HCl to give CaCl₂and CO₂according to the reaction, CaCO₃+ 2HCl --> CaCl₂+ H₂O

What mass of CaCO3 is required to react completely with 25mL of 0.75 HCl?

Calcium carbonate reacts with aqueous HCl to give CaCl₂ and CO₂ according to the reaction, CaCO₃₍_s₎ + 2 HCl₍_aq₎ → CaCl₂₍_aq₎ + CO₂₍_g) + H₂O₍_l₎

What mass of CaCO₃ is required to react completely with 25 mL of 0.75 M HCl?

Join BYJU'S Learning Program

What mass of CaCO3 is required to react completely with 25ml of 0.75M of HCL.

What mass of CaCO₃ is required to react completely with 25ml of 0.75M of HCL.