What occurs in the following reaction?
${N H}_{4}^{+} + H_{2} O ⇋ {N H}_{3} + H_{3} O^{+}$

Electron transfer

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Neutralization

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Double replacement

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Proton transfer

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Solution

The correct option is D
Proton transfer

${N H}_{4}^{+} + H_{2} O ⇌ {N H}_{3} + H_{3} O^{+}$
It is simply proton transfer since no solvent molecule $(H_{2} O)$ is producing which happens in neutralization reaction.

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Similar questions

{N H}_{4}^{+} + H_{2} O ⇋ {N H}_{3} + H_{3} O^{+}

N H_{4}^{+} + H_{2} O ⇋ N H_{3} + H_{3} O^{+}

N H_{3} + H_{2} O \to N H_{4}^{+} + O H^{-}

{N H}_{4}^{+}, H_{2} O, H_{3} O^{+}, H F

{O H}^{-}

{C O}_{3}^{2 -} + H_{2} O ⇌ {H C O}_{3}^{-} + {O H}^{-}

{C O}_{2} + H_{2} O ⇌ H_{2} {C O}_{3}

{N H}_{3} + H_{2} O ⇌ {N H}_{4} O H

H C l + H_{2} O ⇌ {C l}^{-} + H_{3} O^{+}

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