What temperature would be necessary to double the volume of a gas, initially at S.T.P., If the pressure is decreased to 50%

Open in App

Solution

=273 K =?

=1 ATMOS. PRESSURE ATMOS. PRESSURE

=V =2 V

$fraction numerator P subscript 1 V subscript 1 over denominator T subscript 1 end fraction equals fraction numerator begin display style P subscript 2 V subscript 2 end style over denominator begin display style T subscript 2 end style end fraction$

$T subscript 2 equals fraction numerator begin display style 1 half end style cross times 2 V cross times 273 over denominator V end fraction$

T2 = 273 Kelvin

or T2 = 0°Celsius

Note: Hence, the temperature is constant and vary the Pressure and volume, it is nothing but Boyles gas law.

Suggest Corrections

Similar questions

75^{\circ} C

15

75^{0} C

75^{o} C

15 %

Join BYJU'S Learning Program