What volume of oxygen at STP is required to affect the combustion of 11 litres of ethylene at 273 C and 380 mm of Hg pressure?

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Solution

C2H4 + 3O2 -------------> 2CO2 + 2H2O
Let no. of mole of C2H4 is n
pressure = 380/760 atm = 1/2 atm

or one mole of combustion of C2H4 3mole of O2 is required

so for

0.123 mole = 30.123 mole O2 required

= 0.369mole

volume of one mole gas at stp = 22.4L

volume of 0.369 mole O2 at stp = 22.40.369 = 8.27L

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