What will be the angle of reflection if a ray is incident upon a smooth surface POQ as shown below ?

30^{\circ}

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40^{\circ}

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50^{\circ}

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60^{\circ}

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Solution

The correct option is A $30^{\circ}$
Given, $∠ A O P = 60^{\circ}$

As ON is perpendicular to POQ
$∠ A O P + ∠ A O N = 90^{\circ}$

$⟹ ∠ A O N = 90^{\circ} - 60^{\circ}$
$∠ A O N, i . e . a n g l e o f i n c i d e n c e = 30^{\circ}$

By laws of reflection,
Angle of incidence = Angle of reflection
$⟹ ∠ A O N = ∠ B O N$
Thus,
$A n g l e o f r e f l e c t i o n ∠ B O N = 30^{\circ}$

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Similar questions

A ray OA is incident upon a smooth surface POQ. It is reflected back along OB, a normal ON is drawn perpendicular to the surface at O (the point of incidence) and the value of $∠ A O P$ is $60^{\circ}$ . Find the value of x.

A ray OA is incident upon a smooth surface POQ. It is reflected back along OB. A normal ON is drawn perpendicular to the surface at O (the point of incidence). The value of $∠ A O P$ is $60^{\circ}$ . Find the value of the angle of reflection.