What will be the $H^{+}$ ion concentration, when 4g NaOH dissolved in 1000 mL of water:

10^{- 1}

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10^{- 13}

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10^{- 4}

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10^{- 10}

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Solution

The correct option is A $10^{- 13}$
$O H^{-} \Rightarrow \frac{m o l e}{v o l} = \frac{4 / 40}{1000 m} = \frac{1 / 10}{1} = \frac{1}{10} = 10^{- 1}$
$P^{O H} = 1$
$P^{h} = 14 - P^{O H} = 14 - 1 = 13$
$P^{H} = 13$
$(H^{+}) = 10^{- 13}$

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