Question

What will be the height of a cuboid of volume $168m^3,$ if the area of its base is $28m^2?$

Answer 1

$\text{Given: Volume of cuboid}=168m^3$

$\text{Area of its base}=28m^2$

We know that,

$\text{Volume of cuboid}=\text{length}\times \text{breadth}\times \text{height}$

$\text{Area of its base}=\text{length}\times \text{breadth}$

Let the height of cuboid be ${}^{\prime }{h}^{\prime }m$

$\therefore \text{Volume}=l\times b\times h$

$\Rightarrow h=\frac{\text{Volume}}{l\times b}$

$\Rightarrow h=\frac{168}{28}$

$\Rightarrow h=6$

Hence, the height of the cuboid is $6m.$